## CCC '01 J2 - Mod Inverse

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Points: 3
Time limit: 2.0s
Memory limit: 64M

Problem type
##### Canadian Computing Competition: 2001 Stage 1, Junior #2

In many cryptographic applications, the Modular Inverse is a key point. This question involves finding the modular inverse of a number.

Given , where and are integers, the modular inverse of is the unique integer , , such that the remainder upon dividing by is .

For example, , so the remainder when is divided by is , and thus is the inverse of modulo .

You are to write a program which accepts as input the two integers and , and outputs either the modular inverse , or the statement No such integer exists. if there is no such integer .

#### Constraints #### Sample Input 1

4
17

#### Sample Output 1

13

#### Sample Input 2

6
10

#### Sample Output 2

No such integer exists.

• commented on April 2, 2020, 9:32 a.m.

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• commented on Nov. 14, 2019, 8:08 p.m.

I spent two hours head scratching before I realised that I had no output for if there was no possible modinverse. Kill me

• commented on Oct. 19, 2019, 9:23 p.m.

The modular inverse exists only when x and m are coprime. If it exists, the modular inverse is equal to x^(φ(m)-1) % m where φ is Euler's totient function (you can view my submission as an example). The low constraints on this problem make this implementation overkill, however.

• commented on Oct. 19, 2019, 11:41 p.m.

Your solution runs in time though

• commented on Oct. 19, 2019, 3:35 p.m.

I have heard an algorithm to find the mod inverse of a large integer in logarithm time.

• commented on Oct. 27, 2019, 11:11 p.m.

Yes, see the problem https://dmoj.ca/problem/modinv

• commented on Oct. 19, 2019, 5:41 p.m.

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• commented on July 31, 2018, 9:34 p.m. edit 2

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• commented on Sept. 25, 2017, 11:36 p.m.

I don't get this problem, is it supposed to say + instead of x? -> such that the remainder upon dividing x×n by m is 11.