## Editorial for CCC '16 J2 - Magic Squares

Remember to use this editorial

**only**when stuck, and**not to copy-paste code from it**. Please be respectful to the problem author and editorialist.**Submitting an official solution before solving the problem yourself is a bannable offence.**Sum any row or column, and then check if the sum of the remaining rows and columns are identical.

**Time Complexity:**

#### Solution — Python 2

```
S = [[int(s) for s in raw_input().split()] for _ in xrange(4)]
M = True
T = sum([S[0][j] for j in xrange(4)])
for i in xrange(4):
M &= (T == sum([S[i][j] for j in xrange(4)]))
for i in xrange(4):
M &= (T == sum([S[j][i] for j in xrange(4)]))
print 'magic' if M else 'not magic'
```

## Comments