Canadian Computing Competition: 2017 Stage 1, Junior #2
Suppose we have a number like . Let's define shifting a number to mean adding a zero at the end. For example, if we shift that number once, we get the number . If we shift the number again we get the number . We can shift the number as many times as we want.
In this problem you will be calculating a shifty sum, which is the sum of a number and the numbers we get by shifting. Specifically, you will be given the starting number and a non-negative integer . You must add together and all the numbers you get by shifting a total of times.
For example, the shifty sum when is and is is: . As another example, the shifty sum when is and is is .
Input Specification
The first line of input contains the number . The second line of input contains , the number of times to shift .
Output Specification
Output the integer which is the shifty sum of by .
Sample Input
12
3
Sample Output
13332
Comments
the logic is very simply, but you need to be careful when adding them!
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I solved this one by converting a string of all ones to an int.....
I solved it by getting the sum of a list
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Yes, because you submitted an editorial solution to a lot of problems without solving them yourself before. Each editorial is accompanied by a large warning that copy/pasting editorials can lead to bans on submitting a problem, so is it a surprise that you got banned doing so?
I've unbanned you from this problem, but this isn't something that'll happen again.