Editorial for COCI '10 Contest 7 #1 Šećer


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If N is a multiple of 5, it's obviously best to carry only 5-kilogram packages. If this is not the case, we will have to use at least one 3-kilogram package.

From this we derive the following algorithm: use 3-kilogram packages as long as the remaining number is not a multiple of 5, and then use only 5-kilogram packages to use up the remaining sugar.

There are other approaches to solving this task. We could use two loops to try out all the possible combinations of 3 and 5-kilogram packages, and find out which one gives the correct amount of sugar with the least number of packages used.


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