Editorial for COCI '22 Contest 5 #1 Kalendar
Remember to use this editorial only when stuck, and not to copy-paste code from it. Please be respectful to the problem author and editorialist.
Submitting an official solution before solving the problem yourself is a bannable offence.
Submitting an official solution before solving the problem yourself is a bannable offence.
We can create an array consisting of zeroes, the integers from
to
, and then, if necessary, some more zeroes, so that the length of the array is divisible by
. The zeroes represent the missing days, i.e. the ones we will replace with
....
The length of this array divided by is the number of rows the calendar will have. We can now iterate through the array and create the rows: depending on the element of the arrays, we will determine which three characters should we add.
The above described solution is without decorations. We can add them easily: the first and last row are always the same, and all the other rows can be made with a little addition to the solution from above.
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