quantum is not feeling well today, and has decided to create a more painful version of the simple Fibonacci problem.

Recall that the Fibonacci sequence is a well known sequence of numbers in which

$$\displaystyle F(n) = \begin{cases} 0, & \text{if } n = 0 \\ 1, & \text{if } n = 1 \\ F(n-2) + F(n-1), & \text{if } n \ge 2 \end{cases}$$

You are given a number ~N~ ~(1 \le N \le 10^{100\,000})~, find the ~N^{th}~ Fibonacci number, modulo ~1\,000\,000\,007~ ~(= 10^9 + 7)~.

#### Input Specification

The first line of input will have the number ~N~.

#### Output Specification

The ~N^{th}~ Fibonacci number, modulo ~1\,000\,000\,007~ ~(= 10^9 + 7)~.

#### Sample Input

`26`

#### Sample Output

`121393`

## Comments

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Use math.