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Points: 3 (partial)
Time limit: 2.0s
Memory limit: 16M

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Junior 3 — Waiting

Griffy has arrived at Don Mills, but he's too early and there's no one at the school to help him with his coding! He decides to wait until school starts so he can get some pointers (see what we did there?). Given the time he arrives at and the time that school starts, determine how many seconds Griffy will need to wait.

Input Specification

All times will be given in the format HH:MM:SS (0 \le HH \le 23, 0 \le MM \le 59, 0 \le SS \le 59).

First line: Time Griffy arrives (time will be less than 12:00:00).

Second line: Time school starts (time will be less than or equal to 23:59:59).

Note: The time school starts will be strictly greater than the time Griffy arrives.

Output Specification

One line, the number of seconds Griffy will need to wait.

Sample Input

08:15:00
08:30:00

Sample Output

900

Comments


  • -1
    forgetUserName  commented on Feb. 5, 2020, 1:53 p.m.

    I got my case 8 wrong and I am struggling on that. Does anyone know which part I did wrong? Thank you.


  • 1
    quantum  commented on Dec. 8, 2014, 9:31 p.m.

    The problem mentions 23:59:59, but leap seconds can cause the last number to go up to 61.


    • 3
      FatalEagle  commented on Dec. 8, 2014, 9:35 p.m.

      But since we explicitly state the constraint up to 23:59:59, we don't consider leap seconds.


  • -7
    Yuting9  commented on Dec. 8, 2014, 7:52 p.m.

    This comment is hidden due to too much negative feedback. Click here to view it.


    • 4
      Xyene  commented on Dec. 8, 2014, 8:08 p.m.

      There's a 15 minute difference between the times. 15 \times 60 = 900.


      • -2
        Yuting9  commented on Dec. 9, 2014, 12:18 p.m.

        oh, I read it wrong...