First, to simplify implementation, note that we only need to consider additions (deletions can be transformed to additions). Consider a graph where nodes are ~(\text{state}, \text{number of commands followed})~. There are ~50^3~ nodes in this graph, and ~50^3 \times 5~ edges (~1~ edge for following the next valid command, ~4~ edges for inserting an arbitrary command before).

Now, note the shortest path from the ~(\text{robot square}, 0)~ to some node ~(\text{exit square}, t)~ for any ~t~ is the solution.

The edge weights are ~0~ or ~1~, so this can be solved with BFS, though Dijkstra's will also pass.