Editorial for Riolku's Mock CCC S1 - Word Bot
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Submitting an official solution before solving the problem yourself is a bannable offence.
Submitting an official solution before solving the problem yourself is a bannable offence.
Author:
Subtask 1
We can maintain a counter for the amount of consecutive vowels and the amount of consecutive consonants.
When we encounter a vowel, we increment the vowel counter and reset the consonant counter.
When we encounter a consonant, we increment the consonant counter and reset the vowel counter.
If we ever go over the threshold of consonants or vowels, output NO
; otherwise, output YES
.
Time Complexity:
Subtask 2
Use the previous idea except we account for the y
case.
When we encounter a y
, increment both counters and do not reset either of them.
Time Complexity:
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