Hole punched paper in a 3-ring binder! An upgrade over stapled paper!

Nathan is a competitor in the Canadian Computing Olympiad (CCO). To prepare for this difficult competition, he will bring a thick binder full of code samples (even though the CCO disallows paper notes).

Nathan begins by categorizing the pages according to the holes that appear. The rules are stated below:

• A category is a string with a length between ~1~ and ~7~.
• The first letter of the string is -.
• The possible hole locations on the page are labelled from A to F. When a page has a hole, its corresponding letter is in the string.
• The letters in the string will appear in sorted order.

For example, the category -ABF represents a page with holes at A, B, and F. The category -ABCDEF represents a page with holes at all ~6~ locations.

Nathan's binder is slightly unusual. Since he has a massive number of pages, he needs certain holes in certain locations. The page template ~T~ contains all of the holes needed for his pages. Nathan absolutely cannot rotate/flip over any page and put it into the binder, since he needs the extra few seconds to boost his ranking.

Nathan will put ~N~ pages into his binder. Can you tell him whether each page will fit or not?

Input Specification

The first line contains ~T~, the page template.

The second line contains ~N~ ~(1 \le N \le 1000)~.

The next ~N~ lines contain a category. Nathan has a page in this category, and he wants to put it into the binder.

Output Specification

For each of the ~N~ pages, print yes or no on its own line. Print yes if the page can fit into the binder. Print no if additional holes need to be punched.

Sample Input

-ABC
4
-AB
-ABC
-ABCDEF
-DEF

Sample Output

no
yes
yes
no

Explanation for Sample Output

From the template ~T~, there must be holes at A, B, and C for a page to fit into a binder.

The first page is missing hole C, so the output is no.
The second and third pages have the necessary ~3~ holes, so the output is yes.
The fourth page does not have any of the holes, so the output is no.