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Points: 3 (partial)
Time limit: 2.0s
Memory limit: 256M

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Allowed languages
Ada, Assembly, Awk, Brain****, C, C#, C++, COBOL, CommonLisp, D, Dart, F#, Forth, Fortran, Go, Groovy, Haskell, Intercal, Java, JS, Kotlin, Lisp, Lua, Nim, ObjC, OCaml, Octave, Pascal, Perl, PHP, Pike, Prolog, Python, Racket, Ruby, Rust, Scala, Scheme, Sed, Swift, TCL, Text, Turing, VB, Zig
Sample ending logic of a program in Bracket.

Some computer science courses at the University of Fireloo teach a programming language called Bracket.

Two of the functions in Bracket are (car x) and (cdr x). These functions are used a lot, so the Bracket developers allowed programmers to "combine" multiple uses of (car x) and (cdr x) into one name.

Suppose that the function is (cijk...r x), where i,j,k,... are characters each representing either a or d. This function is equivalent to (cir (cjk...r x)), which is equivalent to (cir (cjr (ck...r x))), and so on. Note that the placement of the brackets is important. A full expansion only contains car and cdr functions.

For example, (cadadr x) can be fully expanded to become (car (cdr (car (cdr x)))).

Given a function in the form (cijk...r x), please output the full expansion.

#### Input Specification

The only line of input will contain a string in the form of (cijk...r x). It will contain no more than characters.

For of the points, the string will contain no more than characters.

#### Output Specification

Output a single line, the full expansion of the given function. Ensure that brackets are proper and that there is a space between the last cdr or car and the following x. Other spacing will not matter.

#### Sample Input 1

(cadadr x)

#### Sample Output 1

(car (cdr (car (cdr x))))

#### Sample Input 2

(cdadaddr x)

#### Sample Output 2

(cdr (car (cdr (car (cdr (cdr x))))))