## IOI '14 P5 - Friend

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Points: 30 (partial)
Time limit: 1.0s
Memory limit: 256M

Problem type
Allowed languages
C, C++

We build a social network from people numbered . Some pairs of people in the network will be friends. If person becomes a friend of person , then person also becomes a friend of person .

The people are added to the network in stages, which are also numbered from to . Person is added in stage . In stage 0, person 0 is added as the only person of the network. In each of the next stages, a person is added to the network by a host, who may be any person already in the network. At stage (), the host for that stage can add the incoming person into the network by one of the following three protocols:

• IAmYourFriend makes person a friend of the host only.
• MyFriendsAreYourFriends makes person a friend of each person, who is a friend of the host at this moment. Note that this protocol does not make person a friend of the host.
• WeAreYourFriends makes person a friend of the host, and also a friend of each person, who is a friend of the host at this moment.

After we build the network we would like to pick a sample for a survey, that is, choose a group of people from the network. Since friends usually have similar interests, the sample should not include any pair of people who are friends with each other. Each person has a survey confidence, expressed as a positive integer, and we would like to find a sample with the maximum total confidence.

#### Example

10IAmYourFriend(1, 0)
20MyFriendsAreYourFriends(2, 1)
31WeAreYourFriends(3, 1), (3, 0), (3, 2)
42MyFriendsAreYourFriends(4, 1), (4, 3)
50IAmYourFriend(5, 0)

Initially the network contains only person 0. The host of stage 1 (person 0) invites the new person 1 through the IAmYourFriend protocol, hence they become friends. The host of stage 2 (person 0 again) invites person 2 by MyFriendsAreYourFriends, which makes person 1 (the only friend of the host) the only friend of person 2. The host of stage 3 (person 1) adds person 3 through WeAreYourFriends, which makes person 3 a friend of person 1 (the host) and people 0 and 2 (the friends of the host). Stages 4 and 5 are also shown in the table above. The final network is shown in the following figure, in which the numbers inside the circles show the labels of people, and the numbers next to the circles show the survey confidence. The sample consisting of people 3 and 5 has total survey confidence equal to , which is the maximum possible total confidence.

Given the description of each stage and the confidence value of each person, find a sample with the maximum total confidence. You only need to implement the function findSample.

• findSample(n, confidence, host, protocol)
• n: the number of people.
• confidence: array of length ; confidence[i] gives the confidence value of person .
• host: array of length ; host[i] gives the host of stage .
• protocol: array of length ; protocol[i] gives the protocol code used in stage ): 0 for IAmYourFriend, 1 for MyFriendsAreYourFriends, and 2 for WeAreYourFriends.
• Since there is no host in stage 0, host[0] and protocol[0] are undefined and should not be accessed by your program.
• The function should return the maximum possible total confidence of a sample.

1 11 All three protocols
2 8 Only MyFriendsAreYourFriends
3 8 Only WeAreYourFriends
4 19 Only IAmYourFriend
5 23 All confidence values are 1 Both MyFriendsAreYourFriends and IAmYourFriend
6 31 All three protocols

#### Implementation details

Your submission should implement the subprogram described above, using the following signatures.

##### C/C++ program
int findSample(int n, int confidence[], int host[], int protocol[]);

##### Pascal programs
function findSample(n: longint, confidence: array of longint, host: array of longint; protocol: array of longint): longint;


• commented on Nov. 12, 2016, 12:27 p.m. edited

Why are there subtasks if there's no partial.

Edit: 3dor told me to add partials.

• commented on Nov. 12, 2016, 9:13 a.m.

pascal outline is provided but pascal is not an allowed language?

• commented on Nov. 12, 2016, 10:40 a.m.

We try to be as true to the original problem statement as possible. As for why Pascal is not allowed, this is because there's currently no Pascal signature grader (and Pascal isn't that popular on DMOJ anyways).